vertically upward from the surface of the earth. The rock rises to some maximum
ID: 1521817 • Letter: V
Question
vertically upward from the surface of the earth. The rock rises to some maximum height and falls back toward the surface of the earth. At the highest point, its velocity = 0, its acceleration = 0. its velocity = 0, its acceleration notequalto 0. its velocity notequalto 0, its acceleration = 0. its velocity notequalto 0, its acceleration notequalto 0. A pitcher delivers a fast hall with a velocity of 43 m/s to the north. The batter hits the ball and gives it a velocity of 51 m/s to the south What was the average acceleration of the ball during the 1.0 Times 10^-3 seconds when it was in contact with the bat? 4.3 Times 10^4 m/s^2, north 5.1 Times 10^4 m/s^2, south 9.4 Times 10^4 m/s^2, north 9.4 Times 10^4 m/s^2, south 7.0 Times 10^3 m/s^2, south An ideal gas is slowly compressed to one-half its original volume with no change in temperature. What happens to the average speed of the molecules in this ideal gas? It does not change. It halves. It doubles. It quadruples. When an ideal gas expands adiabatically. heat flows out of the system. there is no work done by the gas. the internal energy of the ideal gas does not change. the internal energy of the ideal gas decreases. the internal energy of the ideal gas increases.Explanation / Answer
Avf, Acceleration,a =( vf - vi)/(tf - ti) = (43-(-51))/(10^(-3)) = 9.4 *10^4 m/s^2 south. So, D is the correct option.
vi is the initial velocity,
vf is the final velocity,
ti is the initial time,
tf is the final time.
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