A parallel-plate capacitor with only air between the plates is charged by connec

Question

A parallel-plate capacitor with only air between the plates is charged by connecting it to a battery. The capacitor is then disconnected from the battery, without any of the charge leaving the plates.

A. A voltmeter reads 44.0 V when placed across the capacitor. When a dielectric is inserted between the plates, completely filling the space, the voltmeter reads 11.0 V . What is the dielectric constant of this material?

B. What will the voltmeter read if the dielectric is now pulled partway out so it fills only one-third of the space between the plates?

Explanation / Answer

A)

Dielectric constant, K = V0/V = 44V /11V = 4

K = 4

B)

Total voltmeter reading is 44.0V

If dielectric inserted then the voltmeter reading is 11.0V

Now the dielectric is pulled partway of out.

it fills only one- third of the space between plates.

So finally voltmeter reading is 44.0V – 11.0V = 33.0V

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