Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Very much appreciated. I need help on these homework problems and I\'ve visited

ID: 1521152 • Letter: V

Question


Very much appreciated. I need help on these homework problems and I've visited my schools tutors but they're not confident in any of the help they give me and on some they just tried to "steer" me in the right direction and it wasn't helpful. I need this to study from to really understand this material. Very much appreciated. I need help on these homework problems and I've visited my schools tutors but they're not confident in any of the help they give me and on some they just tried to "steer" me in the right direction and it wasn't helpful. I need this to study from to really understand this material. I need help on these homework problems and I've visited my schools tutors but they're not confident in any of the help they give me and on some they just tried to "steer" me in the right direction and it wasn't helpful. I need this to study from to really understand this material.

Explanation / Answer


y = m*lambda*R/a


R = distance between screen and slit

a = slit width

lambda = wavelength

for m = 1 and y = 24.2 cm

0.242 = 1*589*10^-9*0.66/a

a = 1.6*10^-6 m


for y = 0.212 , m = 1   and a = 1.6*10^-6 m

0.212 = 1*lambda*0.66/(1.6*10^-6 )


wavelength lambda = 514 nm <<<<<<--------answer


++++++


number of lines / cm = 1/a = 0.01/(1.6*10^-6) = 6250 <<<<<----------answer