Electric field in body cell The electric potential difference across the membran

Question

Electric field in body cell The electric potential difference across the membrane of a body cell is +8.3×102 V (higher on the outside than on the inside). The cell membrane is 8.8×109 m thick. Part A Determine the magnitude of the E field through the cell membrane. Express your answer to two significant figures and include the appropriate units. Ex =

Part B

Determine the direction of the E  field through the cell membrane.

Determine the direction of the  field through the cell membrane.

Explanation / Answer

Part A)

|E| = dV/dx = 8.3*10^-2/(8.8*10^-9)

= 9431818 V/m

Part B

We know E = - dV/dx

i.e. V decreases towards direction of electric field

Hence direction is inward

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