Review example 17-8 in the book (p 735). If the membrane capacitance instead inc

Question

Review example 17-8 in the book (p 735). If the membrane capacitance instead increases at 7.0 × 10-14 F/s during insulin release, how many vesicles fuse with the cell membrane per second? Make sure to give your answer in whole integers rather than rounding the number to one significant figure as done in the book. Assume that the capacitance of the cell membrane is 1.0 ?F/cm2.

I did it and got 7 x 10^-12 but maybe im doing something wrong :( Help!

Solve Find the rate at which the membrane area must increase to cause this rate of capacitance increase. Rate of change of the capacitance of the membrane 1.6 × 10-13 F/s Equation 17-13 tells us that the capacitance C is directly proportional to the membrane surface area Am. We are told that the capacitance per unit area is approximately 1 F/cm, so the change in capacitance Cm that corresponds to a given change in area Am is Since the capacitance increases by 1.6 × 10-13 F in 1 s, the increase in area of the membrane in 1 s must be = (1.6x 10-13 F)( 1 cm = 1.6 × 10-11 m2 (We used 1 F= 1 microfarad = 10-6 F and 1 m= 100 cm.)

Explanation / Answer

Capacitane increases at 7 *10^-14 F/s which is almost half the previous rate.i.e 7/16 timess that of previous rate.

In the previous problem it waasnever mentioned how many vescles fuse at that rate or what will be the rate required to fuse at 1vescle / membrane in how manu seconds.

If the previous number is say x, then now since capacitance increases more slowly fusion takes place slowly and number of vescles fusing will be 7/16 times of the previous fusion vescle. i.e 7/16 x

please refer to textbook for any description and multiply by 7/16 and round it off. unable to get ur textbook on the net.

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