A parallel plate with metal plates, each of area 1.00m_2 is separated by 1.00 mm

Question

A parallel plate with metal plates, each of area 1.00m_2 is separated by 1.00 mm. calculate the capacitance. 8.85 PF 8.85 nF 8.85 mF 8.85  micro F None using the data given in question 1 above, if the voltage is 3.00 times 10^3 V.what is the charge stored in the capacitor? 26.6 mu C 76 mu C 26.6 Mc 29.6 muC none A conductor carries a current of 5A for 4 min, what is the number of electrons that pass through the cross sectional area conductor? 7.50 times 10^23 9.50 times 10^21 7.50 times 10^21 8.50 times 10^21 none.

Explanation / Answer

Capacitance = k x 0 x area / separation
Capacitance = ?
k=1 air
0 = 8.854 10^-12 F/m
area = 1.0 m^2
s = 1*10^-3 m

So,
Capacitance = 1*8.854*10^-12*1/10^-3
= 8.854 10^-9 F

Q = CV
So, Q = 8.854 10^-9 * 3*10^3
= 26.56uC

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