A parallel plate capacitor with plate separation d is connected to a battery. Th

Question

A parallel plate capacitor with plate separation d is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V. (C is the capacitance and U is the stored energy.) Answer the following questions regarding the capacitor charged by a battery. For each statement below, select True or False. After being disconnected from the battery, decreasing d decreases C. After being disconnected from the battery, inserting a dielectric with will decrease V. With the capacitor connected to the battery, increasing d increases U. With the capacitor connected to the battery, increasing d decreases Q. After being disconnected from the battery, inserting a dielectric with will decrease C. With the capacitor connected to the battery, inserting a dielectric with will decrease U.

Explanation / Answer

1) After being disconnected from the battery, decreasing d decreases C. False

Reason - C0 = A*epsilon0/d so on decreasing d C0 increases.

2) After being disconnected from the battery, inserting a dielectric with will decrease V. True.

Reason - V = Q/C as C increases V will decrease.

3) With the capacitor connected to the battery, increasing d decreases Q. False

Reason - Q = CV since V is fixed and C increases so Q will also increase.

4)  After being disconnected from the battery, inserting a dielectric with will decrease C.False

Reason -  C = kC0where k > or equal to 1

5)  With the capacitor connected to the battery, inserting a dielectric with will decrease U.True

Reason- U = Q2/(2*C) since q will remains constant and C = kC0 where C0 = A*epsilon0/d

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