A proton moves with a velocity of V^rightarrow = (2 i with circumflex - 4 j with

Question

A proton moves with a velocity of V^rightarrow = (2 i with circumflex - 4 j with circumflex + k with circumflex) m/s in a region in which the magnetic field is B^rightarrow - (i with circumflex + 2 j with circumflex - k with circumflex) T. What is the magnitude of the magnetic force this particle experiences?_______N -/2 points SerPSE9 29.P009. A proton travels with a speed of 4.90 times 10^6 m/s at an angle of 59^degree with the direction of a magnetic field of magnitude 0.220 T in the positive x-direction. What is the magnitude of the magnetic force on the proton?________N What is the proton's acceleration?_________m/s^2 -/3 points SerPSE9 29.P019. An electron moves in a circular path perpendicular to a constant magnetic held with a magnitude of 5.00 mT. The angular momentum of the electron about the center of the circle Is 4.00 times 10^-25 J-s. Determine the radius of the circular path._________cm Determine the speed of the electron.________m/s

Explanation / Answer

1)

Another way to evaluate v X B is to remember the unit vector circle for cross products. Following around the X clockwise is positive; going around it CCW is negative.

i x j = k

j x k = i

i x k = ( - j)

(2i - 4j + k) x (i + 2j - k) = ?? please do vector product by your self

mag(vxB) = ?

F= q (v x B) =?

where q = +1.6x10^-19 Coul

2)

In this situation, F = q*v*B*sin(theta),

where is q is the charge of a proton

v is the velocity,

B is the magnetic field,

theta is the angle.

(a)

F = (1.60 x 10^-19 C) x (4.90 x 10^6 m/s) x (0.220 T) x sin(59°)

F = 1.4784 x 10^-13 N

The acceleration is given by F / m,

where F is the magnetic field

m is the mass of a proton (1.67 x 10^-27 kg).

(b)

a = (1.4784 x 10^-13 N) / (1.67 x 10^-27 kg)

a = 8.8529 x 10^13 m/s^2

3)

L = mvr

r = sqrt(L / qB)

r = sqrt((4 x 10^-25) / (5 x 10^-3 x 1.6 x 10^-19)

r = 0.02236 m

r = 2.236 cm

v = L / mr

v = (4 x 10^-25) / (9.1 x 10^-31 x 0.02236)

v = 19.66 x 10^6 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.