A 2.5 m long, straight wire carries a current of 1.25 A. An electron travels of
ID: 1517813 • Letter: A
Question
A 2.5 m long, straight wire carries a current of 1.25 A. An electron travels of 10,000 m/s parallel to the wire at point R, 20 cm from the wire. What is the magnetic field due to the were at point B, which is 20 cm from the wire? What is the magnitude of the force exerted by this magnetic field on the electron? What is the direction of the magnetic force? What is the direction of the magnetic field due to the wire below? Choices: Into the page, Out of the page, Up, Down, Left, and Right. Write the answer in the blank space provided. If the space loop is moving is away from the current-carrying wire, what is the direction of the induced current in the wire? Choices: CLOCKWISE, COUNTER-CLOCKWISE, NEITHER. Write your answer beside the diagram. A 60 cm wire is made into a square loop and placed into a constant magnetic field of magnitude 1.50 T painted through the loop. Calculate the induced EMF (voltage) if the loop is suddenly pulled out of the magnetic field in 0.025 s. Assume the loop is placed back into the same magnetic field but this time, the square is made into an equilateral triangle in 4.56s. Calculate the induced EMF. An object is placed 15 cm in front of a convex mirror with a focal length of 30 cm. What is the magnification and the image properties. An object is located 20 cm from a diverging lens having a focal length of 32 cm. Determine the magnification of the image and the image properties.Explanation / Answer
(11)
from the given
object distance u = - 15 cm
image distance v = ?
focal length f = 30 cm
the mirror equation is given by
(1 / f) = (1 / u) + (1 / v)
(1 / 30) = (1 / - 15) + (1 / v)
image distance v = 10 cm
magnification m = - (v / u)
= - (10 cm / - 15 cm)
= 0.666
the image is virtual, erect, dimnished and lies between pole and focus
(12)
using the lens formula
(1 / f) = (1 / v) - (1 / u)
image distance v = - 12.30 cm
object distance u = - 20 cm
magnification m = v / u
= 0.615
the image is virtual, erect, dimnished and lies between pole and focus
(9)
(A) the direction of magnetic field is out of the page.
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