A 2.40 k g frictionless block is attached to an ideal spring with force constant

Question

A 2.40kg frictionless block is attached to an ideal spring with force constant 314N/m . Initially the block has velocity -3.70m/s and displacement 0.270m . Part A Find the amplitude of the motion. A = m SubmitMy AnswersGive Up Part B Find the maximum acceleration of the block. |amax| = m/s2 SubmitMy AnswersGive Up Part C Find the maximum force the spring exerts on the block. |Fmax| = N A 2.40kg frictionless block is attached to an ideal spring with force constant 314N/m . Initially the block has velocity -3.70m/s and displacement 0.270m . A 2.40kg frictionless block is attached to an ideal spring with force constant 314N/m . Initially the block has velocity -3.70m/s and displacement 0.270m . A 2.40kg frictionless block is attached to an ideal spring with force constant 314N/m . Initially the block has velocity -3.70m/s and displacement 0.270m . A 2.40kg frictionless block is attached to an ideal spring with force constant 314N/m . Initially the block has velocity -3.70m/s and displacement 0.270m . Part A Find the amplitude of the motion. A = m SubmitMy AnswersGive Up Part B Find the maximum acceleration of the block. |amax| = m/s2 SubmitMy AnswersGive Up Part C Find the maximum force the spring exerts on the block. |Fmax| = N Part A Find the amplitude of the motion. A = m SubmitMy AnswersGive Up Part B Find the maximum acceleration of the block. |amax| = m/s2 SubmitMy AnswersGive Up Part C Find the maximum force the spring exerts on the block. |Fmax| = N Part A Find the amplitude of the motion. A = m SubmitMy AnswersGive Up Part B Find the maximum acceleration of the block. |amax| = m/s2 SubmitMy AnswersGive Up Part C Find the maximum force the spring exerts on the block. |Fmax| = N Part A Find the amplitude of the motion. A = m SubmitMy AnswersGive Up Part B Find the maximum acceleration of the block. |amax| = m/s2 SubmitMy AnswersGive Up Part C Find the maximum force the spring exerts on the block. |Fmax| = N Part A Find the amplitude of the motion. A = m SubmitMy AnswersGive Up Part A Find the amplitude of the motion. A = m SubmitMy AnswersGive Up A = m A = m SubmitMy AnswersGive Up Part B Find the maximum acceleration of the block. |amax| = m/s2 SubmitMy AnswersGive Up Part B Find the maximum acceleration of the block. |amax| = m/s2 SubmitMy AnswersGive Up |amax| = m/s2 |amax| = m/s2 SubmitMy AnswersGive Up Part C Find the maximum force the spring exerts on the block. |Fmax| = N Part C Find the maximum force the spring exerts on the block. |Fmax| = N |Fmax| = N |Fmax| = N A 2.40kg frictionless block is attached to an ideal spring with force constant 314N/m . Initially the block has velocity -3.70m/s and displacement 0.270m . Part A Find the amplitude of the motion. A = m SubmitMy AnswersGive Up Part B Find the maximum acceleration of the block. |amax| = m/s2 SubmitMy AnswersGive Up Part C Find the maximum force the spring exerts on the block. |Fmax| = N

Explanation / Answer

a)let the amplitude be A.

so conserving energy,

0.5*314*0.27^2+0.5*2.4*3.7^2=0.5*314*A^2

or A=0.421 m

b) a max=w^2A

=(314/2.4)*0.421

=55.08 m/s^2

c)F max=m*amax

=55.08*2.4

=132.194 N

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