A series of thermodynamic processes is shown in a p-V diagram. In process (ab),

Question

A series of thermodynamic processes is shown in a p-V diagram. In process (ab), 320 J of heat are added to the system, and in process (be), 730 J of heat are added. What is the Work done (W) by the system or on the system in process ab? What is the Change in Internal Energy (delta Eint) in process ab? What is the Work done (W) by the system or on the system in process be? What is the Change in Internal Energy (delta Eint) in process be? What is the total heat added (Q) in process abc? What is the Change in Internal Energy (delta Eint) in process abc? What is the Work done (W) by the system or on the system in process ad? What is the Work done (W) by the system or on the system in process dc? What is the Change in Internal Energy (delta Eint) in process adc? What is the total heat (Q) added in process adc?

Explanation / Answer

a) Wab = P*dV

= 0 (since V is constant)

b) use first law of thermodynamics

dQ = delta_Ein + dW

dQ = delta_Ein + 0

==> delta_Ein = dQ

= 320 J

c) WBC = P2*(V2-V1)

= 10*10^4(8 - 4)*10^-3

= 400 J

d) dQ = delta_Ein + dW

==> delta_Ein = dQ - dW

= 730 - 400

= 330 J

e) dQ(abc) = 320 + 730

= 1050 J

f) delta_Ein(abc) = 400 + 330

= 730 J

g) Wad = P1*(V2-V1)

= 4*10^4*(8 - 4)*10^-3

= 160 J

h) Wd = 0

i) delta_Ein(adc) = 730 J

j) Apply, dQ = delta_Ein + dW

= 730 + 160

= 890 J

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