5/2/2016 11:00 PM A s4.2/100 5/2/2016 05:55 PM Gradebook Print Calculator Period

Question

5/2/2016 11:00 PM A s4.2/100 5/2/2016 05:55 PM Gradebook Print Calculator Periodic Table Question 15 of 16 Map A pling You have a 0.705-m-long copper rod with a rectangular cross section of dimensions 0.0525 m by 0.0815 m. You maintain the ends of the rod at 50.1°C and 97.9°C, but otherwise insulate the rod from its environment. Find the heat current through the rod. The thermal conductivity of copper is 385 Wl(m K). Number The heat current is the amount of heat that flows per unit time. Previous Give up & View Solution Check Answer Next xit ® 8 Hint How do the rod's length and cross-sectional area, its thermal conductivity, and the temperature difference between its ends relate to the heat current through it?

Explanation / Answer

a)
given

k = 385 W/(m.k)

L = 0.705 m

A = 0.0525*0.0815

= 0.00428 m^2

dT = 97.9 - 50.1

= 47.8 C

a) The rate of heat transefred, dQ/dt = k*A*dT/L

= 385*0.00428*47.8/0.705

= 111.7 W

b) Heat current inversly proportional to L

Heat current proportional to A

Heat current proportional to k

Heat current proportional to dT

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