A point charge of q=-115nC is placed at the center of a ring of radius 0.48m. th

Question

A point charge of q=-115nC is placed at the center of a ring of radius 0.48m. the electric field is equal to zero at field point P, which is on the axis of the ring and 0.81m from its center. The center amount of charge spread uniformly over the ring is closest to..
I need help! Why is the answer 181nC? A point charge of q=-115nC is placed at the center of a ring of radius 0.48m. the electric field is equal to zero at field point P, which is on the axis of the ring and 0.81m from its center. The center amount of charge spread uniformly over the ring is closest to..
I need help! Why is the answer 181nC? A point charge of q=-115nC is placed at the center of a ring of radius 0.48m. the electric field is equal to zero at field point P, which is on the axis of the ring and 0.81m from its center. The center amount of charge spread uniformly over the ring is closest to..
I need help! Why is the answer 181nC?

Explanation / Answer

Electric field at the center = kq/r^2 = (9*10^9*115*10^-9)/0.48^2 = 4492.2 N/C

Then the point in the center must have some field strength that is

E ring= k x (zQ)/ ((z^2 + R^2)^(3/2)) = 4492.2

Substitute in the values. z =0.81, R = 0.48 m

(9*10^9*0.81*Q)/(0.81^2 + 0.48^2)^(3/2) = 4492.2

Q = 514.6 nC (I didn,t get your answer. Plz recheck your answer)

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