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In the picture below, the two wires carry current i1 and i2, respectively, with

ID: 1514402 • Letter: I

Question

In the picture below, the two wires carry current i1 and i2, respectively, with positive current to the right. The charge q is positive and has velocity v to the right.

If i2 = 0 and i1 is greater than zero, then the magnetic field near charge q points out of the page.
If i2 = - i1 then the force on q equals zero.
If i1 = i2, then the wires are attracted to each other.
If i1 is greater than i2, then the force on q is north.
If i2 = 0 and i1 is greater than zero, then the force on q points into the page.
If v = 0, then the force on q is zero.
If i2 = 0 and i1 is greater than zero, then the force on q is north.

Explanation / Answer

According to fleming left hand rule

F = Q(VxB)

A.)If i2 = 0 and i1 is greater than zero, then the magnetic field near charge q points out of the page.

FALSE

B.)If i2 = - i1 then the force on q equals zero.

FALSE

C.)If i1 = i2, then the wires are attracted to each other.

TRUE

D.)If i1 is greater than i2, then the force on q is north.

TRUE

E.)If i2 = 0 and i1 is greater than zero, then the force on q points into the page

False

F.)If v = 0, then the force on q is zero

TRUE

G.)If i2 = 0 and i1 is greater than zero, then the force on q is north

TRUE

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