In the physics laboratory, Oscar measured the resistance between his hands to be

Question

In the physics laboratory, Oscar measured the resistance between his hands to be 1.7 kO. Being curious by nature, he then took hold of two conducting wires that were connected to the terminals of an emf with a terminal voltage of 100.0 V.
(a) What current passes through Oscar?
(b) If one of the conducting wires is grounded and the other has an alternate path to ground through a 15-O resistor (so that Oscar and the resistor are in parallel), how much current would pass through Oscar if the maximum current that can be drawn from the emf is 1.08 A?
answer in mA

Explanation / Answer

(a) I = 100 / 1700 = .0588 A = 58.8 mA (b) Io Ro = Ir Rr voltage drop Oscar = voltage across resistor I0 = Ir Rr / Ro = 15 * Ir / 1700 = .00882 Ir Io + Ir = 1.08 = (.00882 + 1) Ir = 1.00882 Ir Ir = 1.07 amps so .01 amps (10 mA) passes thru Oscar

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