number of potassium ions within the cell? 3.11 Consider a membrane that is perme
ID: 151381 • Letter: N
Question
number of potassium ions within the cell? 3.11 Consider a membrane that is permeable to Ca* ions. On one side of the membrane the Ca+ concentration is 100 mM, and on the other side of the membrane the Ca2+ concentration is 1 mM·The electric potential ofthe high-concentration side ofthe membrane relative to the low- concentration side of the membrane is +10 mV. How much reversible work is required to move each mole of Ca from the low-concentratiorn side of the membrane to the high-concentration side of the membrane? What is the equilibrium membrane potential 2+ 3.12 The cell membrane is permeable to many different ions. Therefore, the equilibrium membrane potential for the case of multiple ions will dependExplanation / Answer
3.11.From the given question, gibbs energy equals RT log C2/C1
G=RTlog C2/C1
=8.3×300×log 100/1
=2490×2
=4980KJ/mol
Since this is a reversible reaction,gibbs energy is as follows:
Where
G=H-T S
H is enthalpy,T is temperature,S is
Entropy.
Equilibrium membrane potential is defined as the flow of ions in equilibrium state i.e there should be no net flow of ions from both the concentration gradients.Both electrical voltage and chemical voltage should remain same in terms of energy.
3.1.2.membrane potential essentially depends on two factors:
1)selective ion chanels incase of transporters
2)ion concentration gradients across the membrane.Apart from these two,there is a channel seperations leads to establishment of electrical potential gradient.
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