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ID: 1435962 • Letter: N
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number 5
73% Sun Mar 13 11:55:07 AM a E Chrome File Edit View History Bookmarks People Window Help Josh Chapter 7 Impulse and C Sign In or Sign Up I Che C Chegg Study I Guided Sol www.webassign.net /web/Student/Assignment-Responses/last?dep 13047789 O tech Destiny LFG.Net I Thc faculty.pnc.edu/pt Bookmarks Apple YouTube home Attack on Titan 58 Watch L OTR DestinyTracker De Eii App Sp Section 7.4 5. C+ -1.5 points, CJ10 7.P.030.GO My Notes Ask Your Teacher One object is at rest and another is moving. after the collision and mo The two collide in a one-dimensional, completely inelas collision In other words, they stick toge off with a common velocity. Momentum is conserved. The speed of the object that is moving initially is 26 m/s. The masses of the two objects are 2.6 and 8.2 kg. Determine the final speed of the two-object system after the collision for the case (a) the when large-mass object is the one moving initially and the case (b) when the small mass object is the one moving initially ---Select C GO Tutorial ---Select--- by v Additional Materials Section 7.4 6. C+ -1.5 points CJ10 7.P.034 My Notes Ask Your Teacher The drawing shows a collision between two pucks on an a hockey table. Puck A has a mass of 0.022 kg and is moving along the x axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 0.047 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawingExplanation / Answer
a) 8.2kg is moving at 26m/s so the momentum is 26*8.2
after collision total mass is 10.8
since momentum is conserved the speed is
Vf = Vi*M/(m+M)
Vf =26*8.2/10.8 = 19.74m/s
b) 2.6ks is moving at 26m/s momentum is 2.6*26
after collision mass is 10.8
Vf = Vi*m/(m+M)
Vf = 2.6*26/10.8 = 6.25m/s
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