1. A uniformly charged ring with total charge q = 3.10 µC and radius R = 18.5 cm

Question

1. A uniformly charged ring with total charge q = 3.10 µC and radius R = 18.5 cm is placed with its center at the origin and oriented in the xy plane. What is the difference between the electric potential at the origin and the electric potential at the point (0, 0, 39.0 cm)?

2. A proton is fired from very far away directly at a fixed particle with charge

q = 1.12 1018 C.

If the initial speed of the proton is 3.4 105 m/s, what is its distance of closest approach to the fixed particle? The mass of a proton is 1.67 1027 kg.

3. The speed of an electron moving along the y axis increases from 4.15 106 m/s at

y = 10.0 cm

to 7.75 106 m/s at

y = 2.00 cm.

(a) What is the electric potential difference between these two points?

Explanation / Answer

2)

Given that

The mass of a proton is(mp) = 1.67 1027 kg.

q = 1.12 1018 C.

If the initial speed of the proton is (v) =3.4 105 m/s

We know that

    (1/2)mv2 =kQq/r

then the distance of closest approach to the fixed particle is

             r =2kQq/mv2

               =2*9*109*(1.6*10-19)(1.12 1018 C)/(1.67 1027 kg. )(3.4 105 m/s)2

               =1.670*10-11m

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