A toy sled (mass 5 kg) starts out at rest on top of a 10 m hill, and then slides

Question

A toy sled (mass 5 kg) starts out at rest on top of a 10 m hill, and then slides down into a loop of radius 2 m. You may take the entire surface it slides across as frictionless.

Please explain each step and answers. Thank you!

2.) A toy sled (mass 5 kg) starts out at rest on top of a 10 m hill, and then slides down into a loop of radius 2 m. You may take the entire surface it slides across as frictionless. 16m At point A (the top of the loop): (use for parts a-b) a.) How fast is the sled travelling? b.) How large is the normal force acting on the sled? At point B (the side of the loop): (use for parts c-e) c.) How fast is the sled travelling? e.) Calculate the size and direction of the net force acting on the sled.

Explanation / Answer

At point A

From energy conservation:

mgh = 1/2 mv2

v = sqrt(2gh) = sqrt(2*9.8*6) = 10.84m/s

normal force upward

N = m(v2/r -g) = 49*5 = 245N

At point B

From energy conservation

v = sqrt(2gh') = sqrt(2*9.8*8) = 12.52m/s

And normal force

N = mv2/r =5*78.4 = 392N

Part E

Net force at point B

in positive x direction

fx = 392N

and

Fy = mg = 49N downward

So net force

= 395.05 N at 82.87o from the vertical downward direction

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