Using your data from the copper table, determine the specific heat of copper. Sh
ID: 1510763 • Letter: U
Question
Using your data from the copper table, determine the specific heat of copper. Show ALL your work. Compare to the actual value by computing the percent error.
Al, Cu, Pb At Boiling Temp emp H2O at Room Temperature Procedure (1) Fill the heater with water and turn on. (2) Measure the mass of the calorimeter cup, aluminum, lead, and copper and record below (3) Tie a (3) Tie a string around a pencil and around the aluminum as in the picture above on the right. (4) Fill the calorimeter cup with water so that none will spill when the aluminum is placed into it. (5) Measure the mass of the cup with water and record below. Determine the mass of the water (6) Place the pencil over the boiler completely submerging the aluminum without it touching the boiler Allow the water to come to a boil and let it boil for at least 5 minutes. Record the boiling water temperature (7) Place the thermometer into the cool water. Record the value immediately before step (8). (8) Lift the pencil off the boiler removing the aluminum, shake the water off, and place the pencil over the calorimeter cup so that the aluminum is completely submerged and not touching the cup itself. This step should be done quickly so that not much heat is lost to air (9) Stir the water a little with the glass rod. Record the highest temperature measured by the thermometer. Make sure that the thermometer is not touching the metal. (10) Repeat the above steps for Lead and Copper Mass of calorimeter cup:-20-6 g-)O-206 Kg Boiling Temperature: Aluminum Maluminum (kg) cup & Water final of water (°C 0.20 spol-2755 p075 117.2 | 34.5 Lead MLead (kg) Map & Water (kg) Mater (kg)- Ta of initial of water (C) inal of water (C ater(C) Tea of vater (C) Copper Mcopper (kg) Map &wm; r(kg) .M ate (kg) - & Water T, (°C) . T of water (°C) initial of water .S 27.2 34.2Explanation / Answer
Here, Heat lost by copper = Heat gained by water
=> 0.1902 * s * (96.3 - 54.3) = 0.075 * 4186 * (37.2 - 27.2)
=> 8 * s = 3139.5
=> s = 392.43 J/kg.oC --------------------> specific heat of copper
=> actual value of specific heat of copper = 385 J/kg.oC
=> % error = (7.43/385) * 100
= 1.92 %
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