1. What is given a = 0.355 [ms-2] and diameter of disk with uniform mass distrib

Question

1. What is given a = 0.355 [ms-2] and diameter of disk with uniform mass distribution = 18.5 [cm]. = (Use three sig. figs. or N/A if not enough information is given)

2. Using information found in previous question, if the dropping mass is 140[g], then what is ?
= ___ [Nm]
(Use three sig. figs. or N/A if not enough information is given.)

3. I have a plot whose vertical intercept is 0.00422 [Nm]. If the bearings are 2 [mm] from the center of the wheel,then what is the force of friction?
Use three significant figures for your answer in Newton.
____ [N]

Explanation / Answer

1)we know that a = alpha*r

where r is radius ,

so alpha = a/ r = 0.355 /0.0925 = 3.837 rad /s 2

2) torque is given by I * alpha

where I = moment of inertia = 0.5 * m * R2 = 0.5* 0.14* 0.0925 2

= 5.989 x10-4

torque = I* alpha= 5.989 x10-4 * 3.837 = 2.298 x10-3 N-m

3) we want newtons therefore .00422Nm / .002m leaves you with2.11 newtons

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