The magnetic field due to a current I in a long, straight wire has magnitude B a
ID: 1507341 • Letter: T
Question
The magnetic field due to a current I in a long, straight wire has magnitude B at a perpendicular distance R from the wire. The magnitude of the magnetic field due to a current 2I at a distance of 3R from the wire is 2B/9 4B/9 2B/3 4B/3 B what is the smallest equivalent capacitance that can be formed by connecting a 3.0 microfarad (mu F) capacitor and a 6.0 microfarad capacitor 0.5 mu F 2.0 mu F 3.0 mu F 9.0 mu.F 18 mu F Two equal positive charges Q lie on a line as shown below. The magnitude of the resultant electric field due to the two charges is greater at which of the labeled points? A B C D E The magnitude of the resultant electric field due to the two charges a least it which of the labeled points? A B C D E A unit for electric field is newton/coulomb. An equivalent unit is volt/coulomb volt middot coulomb volt/meter volt/meter^2 volt middot meter middot coulomb Changes that can cause an increase in the current I in resistor R_1 include which of the following? I Decreasing the resistance R_1 II Decreasing the resistance R_2 III Decreasing the resistance R_3 I only II only III only I and III only I, II, and III. A rectangular loop of wire is Initially perpendicular to a magnetic field into the plane of the figure as shown above. A current will be induced in the loop by each of the following procedures EXCEPT The magnitude of the magnetic field is increased The magnitude of the magnetic field is decreased The rectangular loop is deformed into a circle of larger area The loop is routed about axis X - X' The loop is routed about an axis that is perpendicular to the page and passes through point CExplanation / Answer
57) B=mu0*I/2*pi*R
if I=2I and R=3R then B'mu0*2I/2*pi*3R=2B/3
So option (C) is answer
58) minimum equivalent resistance C'=C1*C2/C1+C2 = (3e-6*6e-6)/(3e-6+6e-6) = 18e-12/9e-6 =2e-6 answer is B
59) The resultant electric field is greatest at point B as both charges are positive so field adds up and also distance between both charges is least at B
60) The resultant electric field is least at point C as both charges are positive so field cancels to 0.
61) volt/meter
62) Option D is correct as current in R1 depends upon R1 and R3.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.