As a woman walks, her entire weight is momentarily placed on one heel of her hig
ID: 1505394 • Letter: A
Question
As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted on the floor by the heel if it has an area of 1.55 cm2 and the woman's mass is 57.0 kg. Express the force in N/m2 and lb/in2. (In the early days of commercial flight, women were not allowed to wear high-heeled shoes because aircraft floors were too thin to resist such large pressures.)N/m2
lb/in2 As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted on the floor by the heel if it has an area of 1.55 cm2 and the woman's mass is 57.0 kg. Express the force in N/m2 and lb/in2. (In the early days of commercial flight, women were not allowed to wear high-heeled shoes because aircraft floors were too thin to resist such large pressures.)
N/m2
lb/in2
Explanation / Answer
I am using the formula :
P= F/A => F=mg A= 3.14(r^2)
M-57kg
g=9.8 m/sec^2
r^2- (1.55cm^2)^2
Heel pressure = (weight)/(heel area)
The heel area must be expressed as 1.55*10^-4 m^2. The heel pressure is M*g/1.55*10^-4 m^2
(57 kg)(9.8 m/sec^2)
____________________
(1.55m *10^-4)
=>
3.60 * 10^6 N-m or Pa
1.296*10^13N-m^2
14503.800lbin^2
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