I = nqAv_d (I is current, n is electron density, q is unit charge, A is cross se
ID: 1503028 • Letter: I
Question
I = nqAv_d (I is current, n is electron density, q is unit charge, A is cross sectional area, v_d is drift velocity) R = rho (L/A) where R is resistance in ohms, rho is resistivity in ohms-m, L is length in m and A is cross sectional area in m^2 d =v t A(circle) = pir^2 q(e^-) = -1.6 times 10^-19 C If a copper wire has a circular cross sectional diameter of 2 mm and the electron density of copper is 8.342 times 10^28 e^-/m^3, and carries a current of 20.0 A, how long does it are an electron to travel 1 m down the wire?Explanation / Answer
given,
diameter = 2 mm or 2 * 10^-3 m
electron density = 8.342 * 10^28 e/m^3
current = 20 A
distance = 1 m
I = nqAvd
20 = 8.342 * 10^28 * 1.6 * 10^-19 * pi * (1 * 10^-3)^2 * vd
vd = 0.000476969 m/s
distance = velocity * time
1 = 0.000476969 * time
time = 2096.57 sec
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