The figure shows three masses. (figure 1) What is the magnitude of the net gravi

Question

The figure shows three masses. (figure 1) What is the magnitude of the net gravitational force on the m_1 = 25kg mass? Assume m_2 = 10kg and m_3 = 10kg. Submit Part B What is the direction of the net gravitational force on the m_1 = 25kg mass? Assume m_2 = 10kg and m_3 = 10kg. Submit What is the magnitude of the net gravitational force on the m_2 = 10kg mass? Assume m_1 = 25kg and m_3 = 10kg. Submit What is the direction of the net gravitational force on the m_2 = 10kg mass? Assume m_1 = 25kg and m_3 = 10kg. Submit

Explanation / Answer

1. force on m1 due to m2 = Gm1m2/0.2^2 j
force on m1 due to m3 = Gm1m3/0.1^2 i
Net force = 6.67*10^-11 *25 [10j/0.04 + 10i/0.01] = (1.6675i + 0.41687j) 10^-7
|F| = 1.718819*10^-7 N
2. Direction = arctan(0.01/0.04) = 14.0362 deg
3. force on m2 due to m1 = -Gm1m2 j /0.2^2 = -6.67*250 j / 0.04 = -41687.5*10^-11 j N
force on m2 due to m3 = Gm1m3*(0.10 i/sqroot(0.05) - 0.2 j/sqroot(0.05))/(0.04+0.01) = 6.67*10^-11*250(0.44721 i - 0.89442 j)/(0.05) = (14914.4535 i-29829.125j)*10^-11
Net F = (14914.4535 i -71516.625 j )*10^-11
|F| = 73055.2433*10^-11 N
4. arctan(-71516.625/14914.4535) = -78.220 deg

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