The figure shows the net force experienced by a positive test charge located at

Question

The figure shows the net force experienced by a positive test charge located at the center of the diagram. The force comes from two nearby charged balls, one (in red) with a charge of +Q and one (in green) with an unknown charge. (a) Choose the two correct statements, from the list below, about the sign and magnitude of the charge on the second ball. (As with all multiple select questions, you must select all of the correct answers, and only the correct answers, to receive credit for the question.) The second ball has a positive charge. The second ball has a negative charge. There is not enough information here to determine the sign of the charge on the second ball. The magnitude of the charge on the second ball is greater than Q. The magnitude of the charge on the second ball is less than Q. The magnitude of the charge on the second ball is equal to Q. (b) If Q = 6.60 microcoulombs, determine the charge (sign and magnitude) on the second bal. microcoulombs

Explanation / Answer

1. The Green ball has to have a negative charge, in order to give a net force in the desired direction.

2. The magnitude of charge on second ball is greater than Q, because the vector sum is giving a direction which is more inclined towards the green charge i.e. see from the slope, despite the fact that the test charge is at equal distances from both the red and green balls.

3. The unknown charge must be -2 x 6.60= -1.32 microcoulombs.( see from slope of the net direction).

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