A 14 g ovarian tumor is treated using a sodium phosphate solution in which the p

Question

A 14 g ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms are the radioactive ^32P isotope with a half life of 14.3 days and which decays via beta emission with an energy of 1.71 MeV. Half of the sodium phosphate solution is absorbed by the tumor and deposits 9.00 J of energy into it. The other half of the solution is dispersed throughout the patients tissues, also depositing 9 J of energy into the 50.0 kg of body tissues. What is the dose (in Gy and rem) that the tumor receives? What is the dose (in Gy and rem) that the rest of the patient receives? A person is exposed to ionizing radiation which deposits 10 J of energy in their tissue. What dose (in Gy) would an 80 kg adult and a 15 kg child receive under these circumstances? What dose (in rem) would the adult and child each receive if the radiation were low energy- (

Explanation / Answer

37.3 )

a)When ionizing radiation interacts with the human body, it gives its energy to the body tissues. The amount of energy absorbed per unit weight of the organ or tissue is called absorbed dose and is expressed in units of gray (Gy). One gray dose is equivalent to one joule radiation energy absorbed per kilogram of organ or tissue weight. Rad is the old and still used unit of absorbed dose. One gray is equivalent to 100 rads.

So, 10/80 = 0.125 Gy for adult and 10/15 = 0.667 Gy for child

b) 10 J = 108 ergs and 108 ergs/80000 g =12.50 rems for adult and 108 ergs/15000 g = 66.67 rems for child

rem =( 100 ergs/mass in grams)

c)Sievert = J/kg : so, 0.125 sv for adult and 0.667 sv for child

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