A thin film of acetone ( n = 1.25) coats a thick glass plate ( n = 1.50). White

ID: 1500809 • Letter: A

Question

A thin film of acetone (n = 1.25) coats a thick glass plate (n = 1.50). White light is incident normal to the film. In the reflections, fully destructive interference occurs at 650 nm and fully constructive interference at 731 nm. Calculate the thickness of the acetone film.
A thin film of acetone (n = 1.25) coats a thick glass plate (n = 1.50). White light is incident normal to the film. In the reflections, fully destructive interference occurs at 650 nm and fully constructive interference at 731 nm. Calculate the thickness of the acetone film.
A thin film of acetone (n = 1.25) coats a thick glass plate (n = 1.50). White light is incident normal to the film. In the reflections, fully destructive interference occurs at 650 nm and fully constructive interference at 731 nm. Calculate the thickness of the acetone film. A thin film of acetone (n = 1.25) coats a thick glass plate (n = 1.50). White light is incident normal to the film. In the reflections, fully destructive interference occurs at 650 nm and fully constructive interference at 731 nm. Calculate the thickness of the acetone film.

Explanation / Answer

We know that

Lamda(0) =n*lamda =2nt/m

Lamda(0) =650*10-9/1.25 =5.20*10-7m

5.20*10-7m =2t

then t =2.60**10-7m =260nm

Now for the destructive interference

2t =(1+1/2)(731*10-9/1.25)

t =438.6nm

Navigate

A thin film having an index of refraction of 1.50 is surrounded by air. It is il

A thin film of acetone (n = 1.25) coats a thick glass plate (n = 1.50). White li

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.

A thin film of acetone ( n = 1.25) coats a thick glass plate ( n = 1.50). White

Question

Explanation / Answer

Related Questions

Navigate