A particle of mass M1 is traveling with velocity v1 in the positive x direction

Question

A particle of mass M1 is traveling with velocity v1 in the positive x direction on the line y = yo. A second particle of mass M2 is traveling in the positive y direction along the line x = x0. The two particles undergo a perfectly inelastic collision at time to. This occurs on the edge of a Merrygo-Round with a center located at (x1, y10 with a moment of inertia I. The two particles stick to the Merry-go-Round, which starts with an angular speed of o. Find the final angular speed of the system about the center of the Merry-go-Round. sos

Explanation / Answer

the distance from the particles to the center of merry go round is sqrt(xo^2+yo^2)

moment of inertia of the system is I + (M1+M2)*(Xo^2+Yo^2)

using law of conservation of angular momentum

angular momentum before sticking - amguilar momentum after sticking

I*wo = [I + (M1+M2)*(Xo^2+Yo^2)]*wf

wf = (I*wo)/[I + (M1+M2)*(Xo^2+Yo^2)]

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