A 19-cm-diameter circular loop of wire is placed in a 0.91-T magnetic field. art

Question

A 19-cm-diameter circular loop of wire is placed in a 0.91-T magnetic field.

art A

When the plane of the loop is perpendicular to the field lines, what is the magnetic flux through the loop?

Express your answer to two significant figures and include the appropriate units.

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Part B

The plane of the loop is rotated until it makes a 45 angle with the field lines. What is the angle in the equation B = BAcos for this situation?

Express your answer using two significant figures.

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Part C

What is the magnetic flux through the loop at this angle?

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

flux(B)= BAcos(theta)

where theta is the angle between the mag field vector and the normal (perpendicular) to the plane of the circle

a) theta=0 so flux(B) = BA = 0.91T*(pi*0.095m(^2) =.0258Wb

b) theta is the angle between the perpendicular to the loop, so theta = 90-45 = 45

c) flux = BA cos45=.0258cos45=.0182Wb

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