A train car with mass m-1 = 504 kg is moving to the right with a speed of v_1 =

Question

A train car with mass m-1 = 504 kg is moving to the right with a speed of v_1 = 7.6 m/s and collides with a second train car. The two cars latch together during the collision and then move off to the right at v_f = 4.8 m/s. What is the initial momentum of the first train car? What is the mass of the second train car? What is the change in kinetic energy of the two train system during the collision? Now the same two cars are involved in a second collision. The first car is again moving to the right with a speed of v_1 = 7.6 m/s and collides with the second train car that is now moving to the left with a velocity v_2 = -6 m/s before the collision. The two cars latch together at impact. What is the final velocity of the two car system? (A positive velocity means the two fain cars move to the right a negative velocity means the two train cars move to the left.) Compare the magnitude of the momentum of train car 1 before and after the collision: P_1 initial = P_1 final P_1

Explanation / Answer

1) p1i = m1*v1

= 504*7.6

= 3830.4 kg.m/s

2) Apply conservation of momentum

m1*v1 = (m1+m2)*vf

m1*v1/vf = m1+m2

==> m2 = m1*v1/vf - m1

= 504*7.6/4.8 - 504

= 294 kg

3) change in kinetic energy = 0.5*m1*v1^2 - 0.5*(m1+m2)*vf^2

= 0.5*504*7.6^2 - 0.5*(504+294)*4.8^2

= 5363 J

4) m1*v1 + m2*v2 = (m1+m2)*vf

==> vf = (m1*v1 + m2*v2)/(m1+m2)

= (504*7.6 + 294*(-6))/(504 + 294)

= 2.59 m/s

5)
clearly

P1initial < P1final

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.