and I need magnitude for each one? A diverging lens has a focal length of magnit

Question

and I need magnitude for each one?

A diverging lens has a focal length of magnitude 17.8 cm. (a) Locate the images for each of the follewing object distances 35.6 cm distance 36.e location in from at 5.6 Your response differs from the correct answer by more than 100% cm location-infruof BV 17.8 cm distance location intent of 8.9 cm distance 17.8 location ntront of BX (b) Is the image for the object at distance 35.6 real or virtualt? 2x Your response differs from the correct answer by more than 100%, cm real O virtual

Explanation / Answer

By lens formula

1/v = 1/f - 1/u

      = -1/17.8 - 1/35.6 = -3/35.6

magnitude v = 11.87 cm

again,

1/v = -1/17.8 - 1/17.8 = -1/8.9

magnitude v = 8.9 cm

again

1/v = -1/17.8 - 1/8.9 = -3/17.8

magnitude v =5.93 cm

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