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The magnetic field produced by the solenoid in a magnetic resonanceimaging (MRI)

ID: 1498873 • Letter: T

Question

The magnetic field produced by the solenoid in a magnetic resonanceimaging (MRI) system designed for measurements on whole humanbodies has a field strength of 11 T, and the current in the solenoid is 1.5x10^2 A. What is the number of turns permeter of length of the solenoid? Note that the solenoid used toproduce the magnetic field in this type of system has a length thatis not very long compared to its diameter. Because of this andother design considerations, your answer will be only anapproximation.

Explanation / Answer

magnetic feild due to a solenoid solenoid = B = uo*n*I

uo = magnetic permeability = 4*pi*10^-7

n = number of turns per meter

I = current in the solenoid

11 = 4*pi*10^-7*n*1.5*10^2


n = 5.8*10^4 turns /meter