A uniform beam 4.40 m long and weighing 3000 N carries a 3200 N weight 1.50 m fr

Question

A uniform beam 4.40 m long and weighing 3000 N carries a 3200 N weight 1.50 m from the far end, as shown in the figure below (Figure 1). It is supported horizontally by a hinge at the wall and a metal wire at the far end. How strong does the wire have to be? That is, what is the minimum tension it must T= Submit My Answers Give Up Part B What are the horizontal component of the force that the hinge exerts on the beam? Ph= Submit My Answers Give Up Part C What are the vertical component of the force that the hinge exerts on the beam? 600 Submit My Aniswers Give.Up 150 m

Explanation / Answer

torque net = t = 0

0 = t= twall*y + twire* -tbeam - tweight

0 = Fwire*4.40 - 3000*2.2 - 3200*2.9

Fwire = 3609.09 N

part a )

Tcos60 = 3609.09

T = 7218.18 N

part b )

Fh = Tsin60

Fh = 6251.1288 N

part c )

F(y) = 0 = Fh + Tcostheta - 3000N - 3200N

Fh = 2590.9 N

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