STEP BY STEP PLEASE Block A in the figure (Figure 1) hangs by a cord from spring
ID: 1497715 • Letter: S
Question
STEP BY STEP PLEASE
Block A in the figure (Figure 1) hangs by a cord from spring balance D and is submerged in a liquid C contained in beaker B. The mass of the beaker is 1.50 kg ; the mass of the liquid is 2.45 kg . Balance D reads 3.05 kg and balance E reads 7.50 kg. The volume of block A is 3.30×10?3 m3 .
Part A
What is the density of the liquid?
?liquid =
1000
kg/m3
SubmitMy AnswersGive Up
Incorrect; Try Again; 3 attempts remaining
Part B
What will the balance D read if block A is pulled up out of the liquid?
mD =
kg
SubmitMy AnswersGive Up
Part C
What will the balance E read if block A is pulled up out of the liquid?
mE =
4.45
kg
Explanation / Answer
given
The mass of the beaker is 1.50 kg ;
the mass of the liquid is 2.45 kg .
Balance D reads 3.05 kg
and
balance E reads 7.50 kg.
The volume of block A is 3.30 X 103 m3
Part A :
the density of the liquid is d
3.80 X 10-3 X d + 1.5 + 2.45 = 7.5
3.80 X 10-3 X d = 7.5 - 2.45 - 1.5
3.80 X 10-3 X d = 3.55
d = 3.55 / 3.80 X 10-3
d = 934.210 kg/m3
Part B )
the balance D read if block A is pulled up out of the liquid is
mD = weight of the object / ( weight of the object - loss of the weight )
mD = 1.5 / ( 1.5 - 0.95 )
mD = 1.5 / 0.55
mD = 2.72 kg
Part C )
the balance E read if block A is pulled up out of the liquid is
= 1.50 + 2.45
= 3.95 Kg
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.