One of my telescopes is a 90 mm diameter Meade ETX, a type of Maksutov-Cassegrai

Question

One of my telescopes is a 90 mm diameter Meade ETX, a type of Maksutov-Cassegrain. It has an objective with a focal length of 1250 mm. Even though the telescope is a reflecting telescope (uses a mirror instead of a lens as the objective), the formula for the angular magnification is the same. I have two eyepieces, on with a focal length of 26 mm and one with a focal length of 12.4 mm.

(a) What is the magnification when the 26-mm eyepiece is used?



(b) What is the magnification when the 12.4-mm eyepiece is used?

Explanation / Answer

focal length of objective lens f0 = 1250 mm

focal length of eye piece fe = 26 mm

a) magnification m = f0/fe = 1250/26 = 48.07

b)                     m = 1250/ 12.4 = 100.8

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