The body in the figure below is pivoted at O, and two forces act on it as shown.

Question

The body in the figure below is pivoted at O, and two forces act on it as shown. Find an expression for the net torque on the body about the pivot, tau = r_2F_2 cos theta_2- r_1F_1 cos theta_1 tau = r_1F_1 sin theta_1 - r_2F_2 sin theta_2 tau = r_1F_2 cos theta_1 - r_2F_1 cos theta_2 tau = r_2F_1 cos theta_2- r_1F_2 cos theta_1 If r_1 = 1.36 m, r_2 = 2.08 m, F_1 = 3.75 N, F_2 = 4.77 N, theta_1 = 75.0 degree, and theta_2 = 60.0 degree, what is the net torque about the pivot? Include the sign of the value in your answer. Assume counterclockwise rotation to be positive.)

Explanation / Answer

Considering anticlockwise torque to be positive
torque = perpendicular component of the force * radius
a. Net torque = F1sin(theta1)*r1 - F2sin(theta2)*r2
t = r1F1sion(theta1) - r2F2sin(theta2)
b. t = 1.36*3.75*sin(75) - 2.08*4.77*sin(60) = -3.6661 Nm

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