I have a 9 V battery and 3 10ohm resistors. If I hook up the three resistors in
ID: 1494650 • Letter: I
Question
I have a 9 V battery and 3 10ohm resistors. If I hook up the three resistors in series, what is the total current through the circuit? What is the voltage drop across each resistor?) 2. I have a 9 V battery and 3 10ohm resistors. If all three resistors are hooked up to the battery in parallel, what is the current coming out of the battery? What is the current through each of the resistors? What is the voltage drop across each? 3. How much power is radiated by the resistors in Problem 1? How much power is being radiated by the resistors in Problem 2? Which battery do you think would die faster?Explanation / Answer
1) V = 9 V , R =310 ohm
in series combination R =R1+R2 +R3
Rnet = 310+310+310 = 930 ohm
from ohms law V = iR
9 = i*930
i = 0.0097 A
In seris combination current is constant
Voltage across each resistor is V = i*R1 = 0.0097*310 =3 V
2) V = 9 V , R =310 ohm
in series combination 1/R =1/R1+1/R2 +1/R3
Rnet = 310/3= 103.3 ohm
In parallel combination voltage is constant
current acorss each resistor i = 9/310 = 0.029 A
3) power by each resistor P1 = VI = 3*0.0097 = 0.029 W
P2 = VI = 9*0.029 = 0.261 W
P2 >P1
Second battery die faster
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