I have A and B figured out for question 5 but Im stuck on part C and D. Please H
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I have A and B figured out for question 5 but Im stuck on part C and D. Please Help!
Sat Jul 14 1:34:58 PM a E Chrome File Edit View History Bookmarks People Window Help ? 0 ? Chapter 17: Electrochemis 09 ? ? ? fi https://learn .vccs.edu/bbcswebdav/pid-114991424-dt-content-rid-243578735-2/courses/GC297.CHM.112.w0LSU18/GC297.CHM.112.w ?? Q. . Apps Online Banking-Un D Credit Card Account LG HOME-myGCC LG HOME-myNVCC Late Nite Labs Course selected. Plc CU-Central Autho e FOREVER CHORDS b 4b) CChegg Study | Guided Solu x Charle x ? » 416 5. The following items are obtained from the stockroom for construction of a galvanic cell two beakers and a salt bridge wire with clips 200 mL of a 1.00 M Mn2 (aq) solution 200 mL of a 1.00 M Au3 (aq) solution, manganese and gold electrodes. ) Draw a galvanic cell, constructed from the items listed above. Label the anode and the cathode and show the direction of the electron flow on your drawing b) Write the balanced cell reaction and calculate AE° for the cell. Show your work for credit Chem OPExplanation / Answer
5. c) The charge on the electrode (q) = i*t, where i is the current in amp. and t is the time in sec.
Therefore, q = 1 amp * 60*60 sec = 3600 C
I hope, here, Mn2+ undergoes oxidation to Mn7+, i.e. 5 moles of electrons are involved.
For 5 moles of electrons - 1 equivalent of Mn2+ will dissolve.
i.e. For 5 Faradays of charge = 1 equivalent of Mn2+ will dissolve.
For 3600 C of charge, the no. of equilvalents of Mn2+ dissolved = (3600/482500) * 1 = 0.0373 equivlents = 0.0373*5 = 0.1865 moles
And the no. of moles of Au deposited = (3/5)*0.1865 = 0.1119 moles
Explanation: Mn2+/Mn7+ (7-2 = 5 electrons), and Au3+/Au (3-0 = 3 electrons).
d) After 3 h, The concentration of Mn2+ remaining = (0.2 - 0.1865) mol/0.4 L = 0.0135 M
And the concentration of Au3+ remaining = (0.2 - 0.1119) mol/0.4 L = 0.22025 M
Note: If the processes Mn2+/Mn7+ (7-2 = 5 electrons), and Au3+/Au (3-0 = 3 electrons) are not correct, then follow according to the correct values that you may have. But I'm pretty sure that the prodcedure given is undoubtedly correct.
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