Exercise 23.25 A thin spherical shell with radius R4.00 cm is concentric with a

Question

Exercise 23.25 A thin spherical shell with radius R4.00 cm is concentric with a larger thin spherical shell with radius 6.00 cm. Both shells are made of insulating material. The smaller shell has charge q1 = +6.00 nC distributed uniformly over its surface, and the larger shell has charge q2- 9.00 nC distributed uniformly over its surface. Take the electric potential to be zero at an infinite distance from both shells Part A What is the electric potential due to the two shells at the following distance from their common center r = 0? Express your answer with the appropriate units V- Value Units alne Submit My Answers Give Up Part B What is the electric potential due to the two shells at the following distance from their common center r = 5.00 cm ? Express your answer with the appropriate units. V- Value Units alne Submit My Answers Give Up Part C What is the electric potential due to the two shells at the following distance from their common center r = 7.00 cm ? Express your answer with the appropriate units. V- Value Units alne Submit My Answers Give Up

Explanation / Answer

A. Potential inside a shell = kQ/R
so for the given question
V(r = 0) = Potential due to smaller shell + potential due to largeer one
V(r = 0) = k(6*10^-9)/0.04 - k*9*10^-9/0.06 = 0
B. At r = 5 cm
potential due to smaller sphere = kQ/r = k*6*10^-9/0.05
potential due to larger sphere = k(-9*10^-9)/0.06
V = V1 + V2 = -269.4 V
C. At r = 7 cm
potential due to smaller sphere = kQ/r = k*6*10^-9/0.07
potential due to larger sphere = k(-9*10^-9)/0.07
V = V1 + V2 = -384.857 V
D. potential at r = 0.04m = k[6*10^-9/0.04 - 9*10^-9/0.06]
potential at r = 0.06 m = k[6*10^-9/0.06 - 9*10^-9/0.06]
dV = -449 V
E. The inner shell is at potential 0
The outer shell is at negative potential
hence the inner shell is at highrer potential

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