A blue car with mass m_c = 433 kg is moving east with a speed of v_c = 21 m/s an

Question

A blue car with mass m_c = 433 kg is moving east with a speed of v_c = 21 m/s and collides with a purple truck with mass m_t = 1293 kg that is moving south with a speed of v_t = 10 m/s. The two collide and lock together after the collision. What is the magnitude of the initial momentum of the car? What is the magnitude of the momentum of the car-truck combination immediately after the collision? What is the speed of the car-truck combination immediately after the collision? Compare the initial and final kinetic energy of the total system before and after the collision: KE_i = KE_f KE_i > KE_f KE_i

Explanation / Answer

PART 1

m1.v1 = 433 x 21 = 9093

PART 2

Truck = m2.v2 = 1293 x 10 = 12930

PART 4

let common velocity after collision = Vx in east and vy in south

then by moment conservation ;

Car truck momentum = sqrt (9093 ^2 + 12930^2) = 15807.199

PART 3

angle = tan^-1 (12930/9093) = 54.88 South of eats

PART 5

velocity = 15807.199 /(483+ 1293) = 8.9 m/s

PART 6

Ke.i = Ke f

by conservation of enrgy

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