You want to hang a 13-kg sign that advertises your new business. To do this, you

Q: You want to hang a 13-kg sign that advertises your new business. To do this, you

given M = 13 kg m = 5 kg L = 4 m theta = 37 degrees let T is the tension in the cable. Apply, net torque about pivot = 0 m*g*(L/2)*sin(37) + M*g*L*sin(37) - T*L*sin(90) = 0 T = m*g*(1/2)*sin(37) + M*g*sin(37) = 5*9.8*(1/2)*sin(37) + 13*9.8*sin(37) = 91.4 N

ID: 1492094 • Letter: Y

Question

You want to hang a 13-kg sign that advertises your new business. To do this, you use a pivot to attach the base of a 5.0-kg beam to a wall (Figure 1) . You then attach a cable to the beam and to the wall in such a way that the cable and beam are perpendicular to each other. The beam is 4.0 m long and makes an angle of 37? with the vertical. You hang the sign from the end of the beam to which the cable is attached.

What must be the minimum tensile strength of the cable (the minimum amount of tension it can sustain) if it is not to snap?

Explanation / Answer

given

M = 13 kg

m = 5 kg

L = 4 m

theta = 37 degrees

let T is the tension in the cable.

Apply, net torque about pivot = 0

m*g*(L/2)*sin(37) + M*g*L*sin(37) - T*L*sin(90) = 0

T = m*g*(1/2)*sin(37) + M*g*sin(37)

= 5*9.8*(1/2)*sin(37) + 13*9.8*sin(37)

= 91.4 N

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You want to hang a 13-kg sign that advertises your new business. To do this, you

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