A 85.9-kg horizontal circular platform rotates freely with no friction about its
ID: 1491684 • Letter: A
Question
A 85.9-kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.73 rad/s. A monkey drops a 8.35-kg bunch of bananas vertically onto the platform. They hit the platform at 4/5 of its radius from the center, adhere to it there, and continue to rotate with it. Then the monkey, with a mass of 22.1 kg, drops vertically to the edge of the platform, grasps it, and continues to rotate with the platform. Find the angular velocity of the platform with its load. Model the platform as a disk of radius 1.97 m.
Explanation / Answer
let
M = 85.9 kg
R = 1.97 m
wi = 1.73 rad/s
m1 = 8.35 kg at r1 = (4/5)*R = (4/5)*1.97 = 1.576 m
m2 = 22.1 kg at r2 = R = 1.97 m
Initial moment of Intertia of the platform, Ii = 0.5*M*R^2
= 0.5*85.9*1.97^2
= 166.7 kg.m^2
final moment moment of inertia of plafrom and monkeys,
If = = 0.5*M*R^2 + m1*r1^2 + m2*r2^2
= 0.5*85.9*1.97^2 + 8.35*1.576^2 + 22.1*1.97^2
= 273.2 kg.m^2
Apply conservation of angular momentum
Ii*wi = If*wf
==> wf = Ii*wi/If
= 166.7*1.73/273.2
= 1.06 rad/s <<<<<<<-----------------Answer
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