at a given constant, an 8 kg block is sliding to the right with a velocity of 5

Question

at a given constant, an 8 kg block is sliding to the right with a velocity of 5 m/s and someone is pushing on the block with a force of 40 N directed 25 degrees below the horizontal. There is also a 10N frictional force on the block from the surface along which it is sliding. what is the acceleration of the block at this instant?

A) 4.5 m/s^2 B) 0.9 C) 3.8 D) 5 E) 3.3

nstant, an 8 kg block is sliding to the right with a v the block with a force of 40 N directed 25 degree onal force on the block from the surface along w of the block a this instant? 25 40 N 8

Explanation / Answer

forces on block

F*cos(theta) - f = ma

40cos25 - 10 = ma

26.25 = 8*a

a = 3.28 m/s2

ANSWER is E.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.