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ID: 1778816 • Letter: A
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asterin -MP Secure | https://session.masteringphysics.com/myct/itemView?assignmentProblemID-86280225 F17-MP3 Problem 4.52 Resources « previous | 8 of8 | return to assignment Problem 4.52 Part A Ships A and B leave port together. For the next two hours, ship A travels at 40.0 mph in a direction 20.0° west of north while the ship B travels 40.0° east of north at 20.0 mph What is the distance between the two ships two hours atter they depat? Express your answer with the appropriate units Value Units Submit My Answers Give Up Part B What is the speed of ship A as seen by ship B? Express your answer with the appropriate units alue Units Submit My Answers Give Up Continue 3:00 PM 015/2017Explanation / Answer
Turn them into vectors (calculate each one's x and y speed) and subtract A from B
Turn the resultant vector into a speed and direction
Ship A
x = 40 x sin(340) = -13.68 mph
y = 40 x cos(340) = 37.58 mph
Ship B
x = 20 x sin(40) = 12.85 mph
y = 20 x cos(40) = 15.32 mph
B - A:
x = 12.85 - (-13.68) = 26.53 mph
y = 15.32 - 37.58 = -22.26 mph
Relative speed = sqrt ( x^2 + y^2) = sqrt (26.53 ^2 + 22.26 ^2) = 590.55 mph
Distance between two ships after 2 h = 590.55*2 = 1181.11 miles
Spedd of Ship A as seen by B = 590.55 mph
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