A 63 kg object falls freely from rest and strikes the ground. During the collisi

Question

A 63 kg object falls freely from rest and strikes the ground. During the collision with the ground, the object comes to rest on a time of 0.040 sec. The average force exerted on it by the ground is 18000 N, where the upward direction is taken to be the positive direction. From what height did the object fall? Assume that the only force acting the object during the collision is that due to the ground. A 63 kg object falls freely from rest and strikes the ground. During the collision with the ground, the object comes to rest on a time of 0.040 sec. The average force exerted on it by the ground is 18000 N, where the upward direction is taken to be the positive direction. From what height did the object fall? Assume that the only force acting the object during the collision is that due to the ground. A 63 kg object falls freely from rest and strikes the ground. During the collision with the ground, the object comes to rest on a time of 0.040 sec. The average force exerted on it by the ground is 18000 N, where the upward direction is taken to be the positive direction. From what height did the object fall? Assume that the only force acting the object during the collision is that due to the ground.

Explanation / Answer

Impulse is given by

m2v2-m1v1 = F*t

m2v2 = f*t

v2 = f*t/m2 = 18000*0.04/63 = 11.428 m/s

v^2 = 2*a*s

m*v^2 = 2*f*s

s = m*v^2/2f

s = 63*11.428^2/2*18000 = 0.228 m

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