A capacitor for which C = 15 mF is connected to an AC source. The source emf is

Question

A capacitor for which

C = 15 mF is connected to an AC source. The source emf is given by E = Emaxsint, with Emax = 7.0 V and = 20 s1.

Part A (with detalied solution please)

What is the amplitude of the current through the capacitor?

Express your answer with the appropriate units.

imax =

Part B

How does the current amplitude change as you increase the source angular frequency?

The current amplitude increases.

The current amplitude increases.

Explanation / Answer

a)

Current = V/reactance = V/ Xc = V*2*pi*f*C = 7*20*15*10^-3 = 2.1 A

b)

As Source angular frequency is increased, Current amplitude increases, as the relation ship between then as seen in part a is linear

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