A capacitor C is charged to an initial potential of 60.0 V, with an initial char
ID: 1264981 • Letter: A
Question
A capacitor C is charged to an initial potential of 60.0 V, with an initial charge of Q0. It is in a circuit with a switch and an inductor with inductance L = 5.87
A capacitor C is charged to an initial potential of 60.0 V, with an initial charge of Q0. It is in a circuit with a switch and an inductor with inductance L = 5.87?10-2 H and resistance RL. dynamically generated plot 1)Calculate the energy in the circuit after a time of 16 periods. Note that the curve passes through a grid intersection point. 2)Calculate the time required for 89% of the initial energy to be dissipated. At t=0, the switch is closed, and the curve below shows the potential V across the capacitor as a function of time t.Explanation / Answer
From graph , time period, T = 1/13 = 0.077 mili sec.
From the graph it can be assume that the voltage after 16 time period = 25 Volt
So energy store in the capacitor = 1/2 CV2 =0.5*C*252
The information in the question is incomplete so I am getting problem to solve it.
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