A screen with two closely spaced slits, s1 and s2, is illuminated with concrent

Question

A screen with two closely spaced slits, s1 and s2, is illuminated with concrent light at wavelength 600 nm. An interference pattern is observed with a bright central fringe at 0 and equally spaced light and dark interference fringes on either side at it. The path difference in nm between the mass from the two slits at X where the FOURTH minimum (i.e., the FOURTH dark fringe ) from the center is observed is: 2100 300 900 1500 A thin stab of material at thickness 12.0 mu m is placed over slit S1. The refraction index at the material is 1.900 which at the following statement is true. The FOURTH minimum will still be formed at X and the distance between adjacent minima will be uncharged. The FOURTH minimum will no longer be formed at X but the distance between adjacent minima will be uncharged. The FOURTH minimum will still be formed at X but the distance between adjacent minima will change. The bright fringe originally at O will replace the dark fringe formerly at X.

Explanation / Answer

Q1 ) for fourth dark fringe Deltax = pathdifference = 7*wavelength /2

delta X = 3.5 * wavelength

path differenc = 2100 nm

ANSWER A ) 2100

Q2) B) answer

B) The fourth minimum will no longer be formed at X but the distance between adjacent minima will be unchanged

as y = D deltax /d

since y only depends on path difference adjacent minima will not change

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