Your 1.50 x 10^4 N car travels (without skidding) around a horizontal curve of r

Question

Your 1.50 x 10^4 N car travels (without skidding) around a horizontal curve of radius 100 m at a constant speed of 20.0 m/s. The frictional force which the road exerts on your car has a magnitude of The minimum coefficient of static friction between your tires and the road is Your 1.50 x 10^4 N car gets stuck in the snow. Grandps, of mass 80 kg, stands on level ground and tries to move your car. He manages to exert a 450 N force on your car, directed 30 degrees above the horizontal. Find the magnitude of the normal which the ground exerts on Grandipa's feet. The horizontal component of the force which your car exerts on Grandpa has a magnitude of an object has zero resultant force acting or, is there object must be at rest?

Explanation / Answer

Here ,

31 .

as frictional force = m * v^2/R

frictional force = (1.5 *10^4/9.8) * 20^2/100

frictional force = 6.12 *10^3 N

the frictional force is 6.12 *10^3 N

32.

let the coefficient of friction is u

u = frictional force/normal force

u = 6.12 *10^3 N / 1.5 *10^4

u = 0.408

the coefficient of friction is 0.408

33.

force by grandpa , F = 450 N

Normal force on grapdpa feet , FN = mg + F * sin(30)

FN = 80 * 9.8 + 450 * sin(30)

FN = 1009 N

the magnitude of normal force is 1009 N

34.

horizontal component of force exerted on grandpa = F * cos(30)

horizontal component of force exerted on grandpa = 450 * cos(30)

horizontal component of force exerted on grandpa = 389.7 N

the horizontal component of force exerted on grandpa is 389.7 N

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